Coronavirus: Inside pictures of an Italian hospital's COVID-19 unit Photogallery

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Medical staff inside the intensive care unit at the San Raffaele hospital in Milan treat patients with coronavirus.

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Coronavirus: Inside pictures of an Italian hospital's COVID-19 unit

Members of the medical staff in protective suits treat a patient suffering from coronavirus disease (COVID-19) in an intensive care unit at the San Raffaele hospital in Milan, Italy.
(Reuters)

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Members of the medical staff in protective suits treat a patient suffering from coronavirus disease (COVID-19) in an intensive care unit at the San Raffaele hospital in Milan, Italy.
(Reuters)

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Members of the medical staff in protective suits pose for a photo in the COVID-19 intensive care unit at the San Raffaele hospital in Milan, Italy. (Reuters)

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Members of the medical staff in protective suits treat a patient suffering from coronavirus disease (COVID-19) in an intensive care unit at the San Raffaele hospital in Milan, Italy.
(Reuters)

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A member of the medical staff in a protective suit treats a patient suffering from coronavirus disease (COVID-19) in an intensive care unit at the San Raffaele hospital in Milan, Italy. (Reuters)

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Members of the medical staff in protective suits treat a patient suffering from coronavirus disease (COVID-19) in an intensive care unit at the San Raffaele hospital in Milan, Italy. (Reuters)

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Members of the medical staff in protective suits treat a patient suffering from coronavirus disease (COVID-19) in an intensive care unit at the San Raffaele hospital in Milan, Italy.

(Reuters)

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A member of the medical staff in a protective suit treats a patient suffering from coronavirus disease (COVID-19) in an intensive care unit at the San Raffaele hospital in Milan, Italy. (Reuters)

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Members of the medical staff in protective suits watch monitors of patients suffering from coronavirus disease (COVID-19) in an intensive care unit at the San Raffaele hospital in Milan, Italy. (Reuters)

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Members of the medical staff in protective suits treat a patient suffering from coronavirus disease (COVID-19) in an intensive care unit at the San Raffaele hospital in Milan, Italy.
(Reuters)

See more of : coronavirus